Question

6. The length of longest rod that can be placed in a rectangular room of dimensions 10m x 10m x 5m is?
OR
Find the volume of a cube, whose sum of all sides is 36cm.​

Answer 1

Answer:

Sum of all sides of cube = 36

let side = x

ATQ

12x=36

x= 36

12

x=3

therefore volume = S³

= (3)³=27 cm³

Answer 2

Answer:

15m OR 27cm^3

Step-by-step explanation:

6.)

Here, the dimensions of the room are 10m x 10m x 5m

Therefore,

length = 10m

breadth = 5m

height = 10m

This forms a room in shape of cuboid.

So,

=>

length of longest rod that can be placed in a cuboidal room = length of diagonal of the cuboid

=> diagonal of cuboid =√l^2 + b^2 + h^2

                                    = √(10)^2 + (5)^2 + (10)^2

                                    = √100 + 25 + 100

                                    = √225

                                    = 15m

∴ The length of the required rod is 15m

OR

Here,

sum of all side of cube => 12a = 36cm

                                             a = 36/12

                                             a = 3cm          

We know that,

Volume of cube = a^3

                           = (3)^3  

                           = 27 cm^3

∴ The volume of required cube is 27 cm^3