6) The length of the chord of a circle is 8 cm and
perpendicular distance between centre and the
chord is 3 cm. Then, the radius of the circle is
equal to
(a) 4 cm (b) 5 cm (c) 6 cm (d) 8 cm
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Step-by-step explanation:
The length of the chord = 8 cm
half length of the chord = 4 cm ......... (1)
perpendicular distance between centre and the chord = 3 cm ........ (2)
according to Pythagoras theorem
(half length of the chord)² + (perpendicular distance between centre and the chord)² = (radius)²
(4)² + (3)² = r²
r² = 16 + 9 = 25
r = 5 cm
The radius of the circle is equal to 5 cm.
Option (c) 5 cm
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