Question

6.
The minimum value of coefficient of friction (u)
such that block of mass '5 kg' remains at rest is
[NCERT Pg. 102]

(1) 0.3
(2) 0.5
(3)0.6
(4) 0.4​

Answer 1

Answer:

Let the system be at rest.

For 3kg block

T - 3g = 0

so T = 3g. - (1)

For 5 kg block

1) For horizontal direction

T - f = 0

T = uN. - (2)

2) For vertical direction

5g = N.- (3)

From (1) (2) (3)

u(5g) = 3g

u = 3/5 = 0.6

So minimum coefficient of friction should be 0.6 so that 5 kg block remains at rest.

Answer 2

Answer:

the answer is 0.5 okay . option second