Question

6. The number of sodium atoms in 2 moles of
sodium ferrocyanide is
(a) 12 x 1023
(b) 26 x 1023
(c) 34 x 1023 (d) 48 x 1023​

Answer 1

Sodium ferrocyanide = Na4Fe(CN)6.

No of atoms = No if moles * advegadros no

Total no of sodium atoms = 4

No of atoms of sodium = 4*2*6.022*10²³ = 48.022*10²³

Hence (d) 48*10²³ is right.