Question

6. The one's digit of a number is 2 more than its
ten's digit. The difference of the reversed
number and the original number is 18. Find
the number.​

Answer 1

Step-by-step explanation:

Let the number 10a+b then b-a =2 …… (1)

If you reverse the number then it is 10b+a, their difference is

= (10b+a)-(10a+b) = 9(b-a)= 18 which is always true because of (1)

So there is no addl info to solve the question

To state differently, any number, which satisfies (1), when it is deducted from its reverse will leave 18

Take 13 (3–1=2) & 31–13 = 18, take 24 (4–2=2) & 42–24=18, take 35 (5-3=2) & 53–35=18

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