Chemistry, asked by anishdheeravath, 9 months ago

6. The percentage of Mohr’s salt is 14.32% Fe 2+ , 9.2% NH 4 + , 49.0% SO 4 2 – , and 27.57% H 2 O. What is the
empirical formula of the compound?

Answers

Answered by ruses
0

Answer:

The percentage composition of Mohr’s salt is as follows:

Fe2+ = 14.32%

NH4 + = 9.20%

SO4 2- = 49%

rest bieng water of crystallisation.

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