Question

6. The perimeter of rectangle sheet is 100 cm. if the length is 35 cm ,find its breadth.
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Answer 1

Given :

• perimeter of rectangle sheet = 100 cm

• length = 35 cm

To find :

• breadth

Formula used :

$\sf \large p = 2(l + b)$

Where :-

• p = perimeter of rectangle
• l = length of rectangle
• b = breadth of rectangle

Solution :

perimeter of rectangle sheet = 100 cm

length = 35 cm

We know that :-

$\implies\sf p = 2(l + b)$

Now put :-

• p = 100
• l = 35

$\implies\sf 100 = 2(35 + b)$

$\implies\sf \dfrac{100}{2} = (35 + b)$

$\implies\sf \dfrac{ \cancel{100} \: \: 50}{\cancel{2} \: \: 1} = 35 + b$

$\implies\sf 50= 35 + b$

$\implies\sf 15 = b$

Answer:

$\sf Breadth \: of \: rectangular \: sheet \: = 15 \: cm</p><p>$

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$\large\bf\red{Additional-Information}$

Area of circle = πr²

Circumference of circle = 2πr

Area of square = (side)²

perimeter of square = 4× side

area of Rhombus = 1/2(diagonal 1)(diagonal 2)

Area of rectangle = length × breadth

Perimeter of rectangle = 2( length + breadth)

Answer 2

Given :-

Perimeter = 100 cm

Length = 35 cm

To Find :-

Area

Solution :-

We know that

Perimeter = 2(l + b)

Let the breadth be b

100 = 2(35 + b)

100 = 70 + 2b

100 - 70 = 2b

30 = 2b

30/2 = b

15 = b

Now,

Area = l × b

Area = 35 × 15

Area = 525 cm²