Question

6. The perpendicular bisectors of the sides of a
triangle ABC meet at I.
Prove that : IA = IB = IC.​

Answer 1

Answer:

To prove that the three perpendicular bisectors of triangle ABC are concurrent, we must show that the third perpendicular bisector goes through point F as well. For purposes of convenience, perpendicular bisectors DF and FE have been shortened to segments FD and FE in Figure 2.

I hope it's help you