English, asked by avidali8022, 3 months ago

6
The point of height of a tower from a separation
50m from its foot its 30. the tower's tallness is​

Answers

Answered by huzaifs673
0

Answer:

Given height of tower CD=50m

Let the height of the building, AB=h

In right angled △BDC,

⇒ tan60

o

=

BD

CD

3

=

BD

50

⇒ BD=

3

50

m

In right angled △ABD,

⇒ tan30

o

=

BD

AB

3

1

=

3

50

h

3

1

=

50

3

h

∴ h=

3

50

=16.66m

∴ The height of the building is 16.66m

Answered by Anushkasengar9454
0

Explanation:

Hope it helps

I have solved it completely for you

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