Question

6. The population of a town in the year 2012 was 1,32,300. If the population of the town increases every
year by 5%, what was the population of the town in the year 2010?​

Answer 1

Answer:

119070

Step-by-step explanation:

Population in 2012 = 1,32,300

Population in 2010 = 1,32,300-10% of 1,32,300 =1,32,300-10/100×1,32,300

=1,32,300 - 13,230

=1,19,070

Hope this answer is correct and if correct then helpful....

THANK YOU

Answer 2

Answer:

The formula for population increase is given by

A=P(1+r)^tA=P(1+r)t

Here,

A = final population, P = initial population, r = rate in decimal, t = time

So, from the given question,

A = 132300

r = 0.05

t = 2

P =?

Substituting the known values, we get

P=132300/(1+0.05)2

P=120000

Therefore, the population in 2010 was 120000.

Hope this is helpful for you.