Math, asked by nahedbaig8gmailcom, 4 months ago

6. The radius of sphere is 7 cm. Find its curved surface area, total surface area
and volume.​

Answers

Answered by rohannayak2369
2

Answer:

,

Step-by-step explanation:

...

...

.....

.....

....

..

.

Attachments:
Answered by SuitableBoy
28

{\huge{\underline{\underline{\bf{\maltese Question}}}}}

Q - The radius of Sphere is 7 cm . Find it's Curved Surface Area , Total Surface Area and Volume .

{\huge{\underline{\underline{\bf{\maltese Answer\checkmark}}}}}

Concept :

• In Sphere , The Total Surface Area is equal to the Curved Surface Area .

• This is because the sphere has only one surface , which is curved , not plane ..

• So , CSA = TSA = 4 π r²

• Volume - It is the space occupied by the 3-D object , unit is in the form of → unit³

• For Sphere , Volume = \dfrac{4}{3} π r³

We have :

  • Radius of Sphere (r) = 7 cm

To Find :

  • CSA = ?
  • TSA = ?
  • Volume = ?

Solution :

# Curved Surface Area / Total Surface Area :

Using the Formula

 \boxed{ \rm \: surface \: area = 4 \pi \:  {r}^{2}}

So ,

 \rm \mapsto \: csa = tsa = 4 \pi \:  {r}^{2}  \:  {cm}^{2}

 \mapsto \rm \: csa = tsa = 4 \times  \frac{22}{7}  \times  {7}^{2}   \:  {cm}^{2} \\

 \rm \mapsto \: csa = tsa = 4 \times  \frac{22}{ \cancel{7}}  \times  \cancel7 \times 7  \: {cm}^{2} \\

 \mapsto \rm \: csa = tsa = 4 \times 22 \times 7 \:  {cm}^{2}

 \large \mapsto \boxed{ \rm \: csa = tsa = 616 \:  {cm}^{2} }

Now ,

# Volume :

Using the Formula

 \boxed{ \rm \: volume =  \frac{4}{3}  \pi \:  {r}^{3} }

So ,

 \rm \mapsto  \: volume =  \frac{4}{3}  \times  \frac{22}{7}  \times  {7}^{3}  \:  {cm}^{3}  \\

 \rm \mapsto \: volume =  \frac{4}{3}  \times  \frac{22}{ \cancel7}  \times  \cancel7 \times 7 \times 7 \:  {cm}^{3}  \\

 \mapsto \rm \: volume =  \frac{4}{3}  \times 22 \times7 \times 7 \:  {cm}^{3}  \\

  \large\rm \mapsto  \boxed{ \rm\: volume =  \frac{4312}{3}  \:  {cm}^{3}   }

or

 \large\mapsto  \boxed{ \rm \: volume = 1437.333 \:  {cm}^{3}}

So , this is the required answer ↑

Attachments:
Similar questions