6. The rate of a reaction becomes four times when the temperature changes from 293 K to 313 K. Calculate the energy of activation (Ea) of the reaction assuming that it does not change with temperature. [R = 8.314 JK-1 mol-1, log 4 = 0.6021] 52800 J mol-1 84600 J mol-1 O 52.8 K Cal mol-1 O 152.8 KJ mol-1
Answers
Answer:
The rate of a reaction becomes four times when the temperature changes from 293 K to 313 K. Calculate the energy of activation (E
2
) of the reaction assuming that it does not change with temperature.
[R=8.314 J/K mol
−1
,log4=0.6021]log
log K
log K 1
log K 1
log K 1
log K 1 K
log K 1 K 2
log K 1 K 2
log K 1 K 2
log K 1 K 2
log K 1 K 2 =
log K 1 K 2 = 2.303R
log K 1 K 2 = 2.303RE
log K 1 K 2 = 2.303RE a
log K 1 K 2 = 2.303RE a
log K 1 K 2 = 2.303RE a
log K 1 K 2 = 2.303RE a
log K 1 K 2 = 2.303RE a (
log K 1 K 2 = 2.303RE a ( T
log K 1 K 2 = 2.303RE a ( T 1
log K 1 K 2 = 2.303RE a ( T 1
log K 1 K 2 = 2.303RE a ( T 1
log K 1 K 2 = 2.303RE a ( T 1 1
log K 1 K 2 = 2.303RE a ( T 1 1
log K 1 K 2 = 2.303RE a ( T 1 1 −
log K 1 K 2 = 2.303RE a ( T 1 1 − T
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4=
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a (
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 −
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2 1
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2 1
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2 1 )
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2 1 )E
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2 1 )E a
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2 1 )E a
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2 1 )E a =0.6021×2.303×8.314×293×
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2 1 )E a =0.6021×2.303×8.314×293× 20
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2 1 )E a =0.6021×2.303×8.314×293× 20313
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2 1 )E a =0.6021×2.303×8.314×293× 20313
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2 1 )E a =0.6021×2.303×8.314×293× 20313
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2 1 )E a =0.6021×2.303×8.314×293× 20313 E
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2 1 )E a =0.6021×2.303×8.314×293× 20313 E a
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2 1 )E a =0.6021×2.303×8.314×293× 20313 E a
log K 1 K 2 = 2.303RE a ( T 1 1 − T 2 1 )log4= 2.303×8.314E a ( T 1 1 − T 2 1 )E a =0.6021×2.303×8.314×293× 20313 E a =52.863kJ