Question

6. The ratio of nitrogen and oxygen by mass present
in a colourless gas is 7: 8. When this colourless
gas combines with O2, it produces 44800 cm3 of
brown-coloured gas at STP. Find out the num-
ber of moles of oxygen that have taken part in the
reaction.
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Answer 1

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QUESTION=The ratio of nitrogen and oxygen by mass present

in a colourless gas is 7: 8. When this colourless

gas combines with O2, it produces 44800 cm3 of

brown-coloured gas at STP. Find out the num-

ber of moles of oxygen that have taken part in the

reaction.

​

ANSWER=The ratio is determined as 7:8 for N:8 for mass calculation.

The 7/14 and denotes by taking 8/16 as the right ratio calculated when divided by molar mass which gives 1/2.

This can be initiated by delivering ½ and ratio is certainly 1:1.

So, the ratio of atoms of N and O is 1:1.

Answer 2

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ANSWER=The ratio is determined as 7:8 for N:8 for mass calculation.

The 7/14 and denotes by taking 8/16 as the right ratio calculated when divided by molar mass which gives 1/2.

This can be initiated by delivering ½ and ratio is certainly 1:1.

So, the ratio of atoms of N and O is 1:1.