Question

6.
The ratio of potential difference across 1 uF
and 5 uF capacitors -

(1) 1:2
(2) 3:1
(3) 1:5
(4) 10:1​

Answer 1

Answer:. 1:5

Explanation:

What u have to do ?

You Have to find the potential difference in the upper four capacitors

And then compare it with p.d of 5uf

Capacitor.

At last the required ratio is 2:10 or 1:5

Pls mark it as brainliest

Answer 2

Answer:

answer is 1:5

Explanation:

Potential distinction is the distinction in the quantity of strength that price providers have among  factors in a circuit. **Measured in Volts: **Potential distinction (p.d.) is measured in volts (V) and is likewise known as voltage.

The emf (electromotive force) is the capability distinction among the terminals of a battery whilst no modern-day is flowing thru an outside circuit whilst the circuit is open. Potential distinction is the voltage throughout the terminals of the battery whilst the modern-day is being drawn from it to an outside.

potential drop over 5 μF capacitor = 10-0 = 10v

:Cep= C1+C2= 1  μF + 3  μF = 4  μF

Cep =C1C2/C1+C2

        = 2 x 2 /2+2

         = 1  μF

V2= 10(1  μF/ 4  μF+ 1  μF)

V2= 2 μF

V1= 10(4/4+1)

V1=8v

potential drp over one 1  μF capacitor = 2v

V2/V1 = 2V /10V

that equal to  1/5 =1:5

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