Math, asked by mokarram0203, 10 months ago

6). The ratio of the costs of two houses is 4:3 and the cost of the second house
4,20,000. Let's find the cost of the first house. If the cost of the first hous
was 70,000 more, then let's find the ratio of their costs.​

Answers

Answered by KajalBarad
6

Cost of first house before the increase was 5,60,000. And the ratio after the increase is 3:2.

1. lets assume cost of first house is H1 and cost of second house is H2. So first ratio of the cost of two houses is given as 4:3 and the cost of second house is given as 4,20,000. Using this we can find the cost of first house as follows.

(H1/H2)=4/3

H1=(4,20,000)*(4/3)

H1=5,60,000 this was the actual cost of first house.

2. Lets see what is ratio if the cost of first house increases by 70,000

new cost of first house new H1=5,60,000+70,000=6,30,000

new ratio=(new H1)/H2=(6,30,000/4,20,000)

new ratio=3/2 or 3:2    [cancelling Numerator and denominator by 21]

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