Question

6 The ratio of the costs of two houses is 4:3 and the cost of the second house 4,20,000. Let's find the cost of the first house. If the cost of the first house was70,000 more, then let's find the ratio of their costs.​

Answer 1

Given,

The ratio of the costs of two houses is $4:3$

The cost of second house is $4,20,000$

Let cost of first house be $x$

$\frac{4}{3}=\frac{x}{4,20,000}\\\frac{4}{3}\times4,20,000=x$

$x= 560000$

According to the question,

The cost of the first house was $70,000$ more

Then,

First house cost $=5,60,000+70,000=6,30,000$

The new ratio of the cost of two houses $=6,30,000:4,20,000\\=3:2$

Therefore, the new ratio of the costs of two houses is $3:2$

Answer 2

Answer:

$3:2$

Step-by-step explanation:

Given data,

The ratio of the costs of two houses is $4:3$

The cost of second house $=420000$

$\Rightarrow 3x=420000$

$\Rightarrow x=140000$

Therefore, the cost of first house $=4\times140000=560000$

And the cost of the second house $=3\times140000=420000$

If cost of the first house was $70000$ more, then the ratio of their costs  

$=560000+70000:420000=630000:420000=3:2$.

Hence, the required ratio is $3:2$.