Question

6.
The resultant of three vectors of magnitudes 1, 2 and 3 units and whose directions are along the
sides of an equilateral triangle taken in the same order is :
(A) 1unit
(B) √6 units (C) √3 units (D) √14 units​

Answer 1

Step-by-step explanation:

Given 6. The resultant of three vectors of magnitudes 1, 2 and 3 units and whose directions are along the sides of an equilateral triangle taken in the same order is

• So we have R^2 = A^2 + B^2 + 2 AB cos theta
• So here  F1 = 1 , F2 = 2, so we get
•             R^2 = F1^2 + F2^2 + 2 F1F2 cos 120
•         So R = √ F1^2 + F2^2 + 2 F1F2 cos 120
•        Or R = √1^2 + 2^2 + 2 (1)(2) cos (90 + 30)
•        Or R = √5 + 4 cos (90 + 30)
•      Or R = √5 – 4 sin 30
•      Or R = √5 – 4 (1/2)  
•         Or R = √5 – 2
•        Or R = √3

Reference link will be

https://brainly.in/question/10354940