Question

6. the sum of ages of 5 children born at the intervals of 3 years each is 50 years. find out the age of the youngest child?

Answer 1

The children are born at intervals of 3 yrs
hence..
Let age of youngest child be x

Age of 2nd child becomes (x+3)

Age of 3rd child becomes x+3+3= (x+6)

Age of 4th child becomes x+3+3+3=(x+9)

Age of 5th child becomes x+3+3+3+3=(x+12)

According to given condition
x + x + 3 + x + 6 + x + 9 + x + 12 = 50

5x + 30 = 50

5x = 50-30

5x = 20

x = 20/5

x = 4

The age of the youngest child is 4 yrs

Answer 2

Answer:

Let the ages of children be x, (x + 3), (x + 6), (x + 9), (x + 12) years.

According to Question now,

➳ x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

➳ 5x + 30 = 50

➳ 5x = 50 - 30

➳ x = 20/5

➳ x = 4 years

Therefore,the age of youngest child is 4 years.