Question

6. The sum of how many terms of the A.P. 22, 20, 18, ... will be zero?
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Answer 1

Answer :-

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let the sum of the numbers be $\mathtt{(n)}$

$\rightarrow$ $\mathtt{let\: a=22}$

$\rightarrow$ $\mathtt{let\: b=20}$

$\rightarrow$ $\mathtt{let\: n=?}$

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$\mathtt\implies$ so, 0= n ÷ 22× 2+(n-1) (n-2)

$\mathtt\implies$ $\mathtt{Or,\: 0=n(46-2n)}$

$\mathtt\implies$ $\mathtt{Now,\: (n=23)}$

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${\boxed{\tt (23) }}$

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#answerwithquality

#BAL

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