Physics, asked by rudragutte900, 1 year ago

6. The sum of the digits of a two-digit number is 16.
The number obtained by interchanging the digits is
less by 18 than the original number. Find that
two-digit number
93
VARIABLES​

Answers

Answered by niruduttabhuyan
1

hey mate..

just tried to help you

Answer:

8

Explanation:

Is the answer correct?

Please mark this as brainliest

Answered by Anonymous
0

Explanation:

Let the two given numbers be a , b

Given that ,

The sum of the digits of a two-digit number is 16.

=} a + b = 16......(1)

Here, the original number is 10a + b

but if digits are interchanged , the number formed is,

10b + a

Given that ,

The number obtained by interchanging the digits is less by 18 than the original number.

=} 10b + a = 10a + b - 18

=} 9b - 9a + 18 = 0

=} b - a + 2 = 0

=} a - b = 2 .......(2)

from 1 & 2

a + b = 16

a - b = 2

-----------------

2a = 18

a = 9

=} b = 16 - 9

=} b = 7

Therefore, the number is

10a + b = 90 + 7 = 97

The number is 97

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