Question

*6. The sum of the first 55 terms of an A.P. is 3300.
Find its 28th term.​

Answer 1

Step-by-step explanation:

$sn = n \div 2(2a + (n - 1)d)$

t28=a+27d__________(1)

s55=3300

3300=55/2(2a+54d)

3300×2/55=2a+54d

120=2a+54d

a+27d=60________(taking common 2)....(2)

hence, t28=60______(from 2 and 1)

I hope this helps you......

t28=60 Mark me as brainlist......

Answer 2

Answer:

I hope it is helpful to you