Question

6. The sum of three consecutive multiples of 12 is 458. Find these multiples.​

Answer 1

Let the multiples of 12 ne x, x+12, x+24.

so

12 + x+12 x+24 = 458

2x+48 = 458

2x = 458 - 48

2x = 418

x = 418÷2

x = 209

so x=209

x+12=221

x+24=223

If any help required tell me.

Answer 2

Pls mark as brainliest answer