Question

6.The sum of three consecutive multiples of 8 is 48 Find these multiples.​

Answer 1

Answer:

the question says sum of three consecutive multiples of 8 is 48.

The first three consecutive multiples of 8 is 8, 16, and 24.

8+16+24=48.

Thus, 8+16+48 is your answer!

Another method:

let the three consecutive multiples be x+8, x+16 and x+24.

Question says that sum of the multiples is 48.

x+8 + x+16 + x+24 = 48

3x+48=48

x=0

Substitute the value of x in x+8, x+16 and x+24.

0+8=8, 0+16=16, 0+24=24.

8, 16 and 24 is your answer!

Hope this helps :D