Question

6. The sum of two consecutive multiples of 7 is 161. Find these multiples.​

Answer 1

Answer:

77,84

Step-by-step explanation:

two consecutive multiple of 7 be

7x, 7(x+1)

sum = 7x+7(x+1)=7x+7x+7=161

14x=154

x=11

two consecutive multiples are

7×11=77

7×(11+1)=7×12=84

hope this helps

Answer 2

• GIVEN:-

The sum of two consecutive multiples of 7 is 161.

• To Find:-

The multiples.

• SOLUTION:-

Let the numbers be x, x+7.

According to the question,

$\large\Longrightarrow{\sf{x+x+7=161}}$

$\large\Longrightarrow{\sf{2x+7=161}}$

$\large\Longrightarrow{\sf{2x=161-7}}$

$\large\Longrightarrow{\sf{x=\dfrac{154}{2}}}$

$\large\Longrightarrow{\sf{x=\dfrac{\cancel{154}}{\cancel{2}}}}$

$\large\therefore\boxed{\sf{x=77}}$

So,

The numbers are:-

x = 77

x + 7 = 77 + 7 = 84

• Now let's verify it:-

$\large\Longrightarrow{\sf{77+84=161}}$

$\large\Longrightarrow{\sf{161=161}}$

$\large\therefore\boxed{\sf{LHS=RHS}}$

Verified.

$\large\green\therefore\boxed{\sf{\green{Two\:consecutive\:multiples\:of\:7\:are\:77\:and\:81.}}}$