Question

6. The sum of two consecutive multiples of 7 is 161. Find these multiples.​

Answer 1

Step-by-step explanation:

Let the first multiple be 7x and next multiple be 7(x+1)

According to the question

(7x)

2

+(7(x+1))

2

=1225

49x

2

+49(x

2

+2x+1)=1225

49(x

2

+x

2

+2x+1)=1225

2x

2

+2x+1=

49

1225

2x

2

+2x+1=25

2x

2

+2x+1−25=0

2x

2

+2x−24=0

x

2

+x−12=0

x

2

+4x−3x−12=0

x(x+4)−3(x+4)=0

(x+4)(x−3)=0

x=3 or x=−4

Since multiples will not be negative so x=−4 is rejected

Consecutive multiple of 7 are 7×3=21 and 7(3+1)=28

Therefore the two consecutive multiples of 7 are 21 and 28

Answer 2

Answer:

77 and 84 are the multiples