Question

6.
the sum of two digit number and the number obtain by interchanging the digits is 143. if the digit at unit place is
3 more than digit at tens place, find the number (3mark)
Lonely do ww.be
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Answer 1

Step-by-step explanation:

Let unit digit be x+3

Let tens digit be x

original no. = 10(x)+x+3

no. obtained by reversing the digits=10(x+3)+x

sum of no.s = 10x+x+3+10x+30+x=143

= 22x+33=143

=22x=143-33

=x=110/22

=x=5

unit digit =x+3=5+3=8

tens digit =x=5

original no. = 10(5)+8 = 50+8=58

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