Question

6. The temperature of an iron
rod is 350° K. It's temperature
in Calcius
57°
O 67°
O 77°
O 87°​

Answer 1

Answer :

If T(C), T(F) and T are the temperature of a body on Celsius, Fahrenheit and Kelvin scales respectively, then

$\bigstar\:\boxed{\bf{\purple{\dfrac{T_C-0}{100}=\dfrac{T_F-32}{180}=\dfrac{T-273}{100}}}}$

From the above relation,

• T(F) = 9/5T(C) + 32
• T = T(C) + 273

ATQ, T = 250K

We have to find value of T(C)$.$

⭆ T = T(C) + 273

⭆ T(C) = T - 273

⭆ T(C) = 350 - 273

⭆ T(C) = 77°C

Cheers!