Question

6.
The thickness of a hollow metallic cylinder is 2 cm. It is 35 cm long and its inner
radius is 12 cm Find the volume of metal required to make the cylinder, assuminal
it is open, at either end.​

Answer 1

Answer:

5720cm²

Step-by-step explanation:

it's thickness = 2cm

radius of inner portion = 12cm

so, radius of outer portion = 12+2 = 14

height of cylinder = 35cm

volume of cylinder = πR²h - πr²h

= πh(R²-r²)

so, = 22/7×35(14²-12²)

= 22×5(196-144)

= 110(52)

= 5720cm² ....ans.

Answer 2

Answer:

$\huge \bold{5720 {cm}^{3} }$

Step-by-step explanation:

$\blue{ \sf{ \underline{ \pink{ \underline{ \purple{given}}}}}}$

thickness of hollow cylinder is 2 cm

length=35cm

Inner radius=12cm

outer radius=12+2=14cm

$\huge \orange{ \fbox{ \fbox{ \red{ \mathfrak{solution}}}}}$

volume volume of wood required to make the cylinder = volume of whole cylinder - volume of hollow cylinder.

$\pi \times {r}^{2} \times h - \pi \times {r}^{2} \times h$

$= \: \: \pi( {r}^{2} - {r}^{2} )h$

$= \frac{22}{7} ( {14}^{2} - {12}^{2} )35$

$= \frac{22}{7} (196 - 144)35$

$= \frac{22}{ \cancel7} \times 52 \times \cancel35$

$= 22 \times 52 \times 5$

$= 5720 {cm}^{3}$

$\bf{hope \: this \: helps \: you }$