Math, asked by neelamgarg091, 10 months ago

6. The value of K for which the system Kx- y - 2 = 0 and 6x - 2y – 3 = 0 have no
solution
(a) 3
(b) -3
(c) 2
(d) None of these.​

Answers

Answered by rudraupadhyay12
0

Answer: (a)

Step-by-step explanation:

a1 =  k

b1 = -1

c1 = -2

a2 = 6

b2 = -2

c2 = -3

for no sol.

a1/a2 equals b1/b2 not equals c1/c2

equating a1/a2 = b1/b2

k/6 = -1/-2

by cross multiplying,

-2k = -6

k = 3

Answered by GouthamGowda47
1

Answer:

By using ratio,

K/6 = -1/-2 = -2/-3

a¹/a² = b¹/b² ≠ c¹/c²

Thus, this sum is parallel graphic representation. Answer A) 3 seems to be the appropriate option.

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