Question

6.The value of p(t) = 2+t+2t^2−t^3 when t=0 is​

Answer 1

2+0+2×0^2-0^3

2+0+0+0

2.

The answer is 2

Answer 2

Answer:

We substitute the variable t=p the given polynomial r(t)=4t

4

+3t

3

−t

2

+6 as follows:

r(p)=4p

4

+3p

3

−p

2

+6

Hence, the value of the given polynomial with t=p is r(p)=4p

4

+3p

3

−p

2

+6.