Question

6. The velocity of a train in a particular direction increases to 60 kilometres per hour
from 30 kms per hour in one minute. If the train moves with a uniform acceleration
during that time, what is its acceleration ? [Ans. 1800 km/(hr):1, IM. Exam. 1982)​

Answer 1

Explanation:

$\sf\underline{Question}$

The velocity of a train in a particular direction increases to 60 kilometre per hour

from 30 km per hour in one minute. If the train moves with a uniform acceleration

during that time, what is its acceleration ?

$\sf\underline{Answer}$

• The velocity of a train increases from 30 kmph to 60 kmph in one minute
• v = 60 kmph = 16.66 m/s
• u = 30 kmph = 8.33 m/s
• t = 1 minute = 60 s
• Acceleration = ?

We know the first equation of motion,

${\boxed {\sf{\color{blue}{v \: = \: u \: + \: at}}}}$

16.66 = 8.33 + a(60)

16.66 - 8.33 = a(60)

8.33 = a(60)

a = $\sf\frac{8.33}{60}$

a = 0.138 m/s²

Therefore, Acceleration = 0.138 m/s²

Answer 2

Hola ⚘⚘

Answer:

• 0.138 m/s²

Explanation:

Given:

• The velocity of a train in a particular direction increases to 60 kilometres per hour from 30 kms per hour in one minute.

Tofind:

• If the train moves with a uniform acceleration during that time, what is its acceleration ?

Calculation:

• v = 60 kmph (16.66 m/s)
• u = 30 kmph (8.33 m/s)
• t = 1 minute (60 s)
• Acceleration = ?

>> v = u + at

>> 16.66 = 30 + a(60)

>> 16.66 - 8.33 = a(60)

>> 8.33 = a(60)

>> a = 8.33/60

>> a = 0.138 m/s²

hence, the acceleration is 0.138 m/s²