Question

6.
The velocity-time graph of a car is given
25
A
B
201
15+
velocity (m/s) -
10+
5+
D
2 3 4 5 6 7 8 9 10 11
Time (sec)-
0 If the car weighs 1000 kg. What is the
distance travelled by the car in first 2 s?
(i) What is the braking force applied at the end of
9 s to bring the car to stop in 2 s?​

Answer 1

Answer:

(a)Since velocity is not changing, acceleration is equal to zero.

(b) Reading the graph, velocity=20ms

−1

(c) s = area of the figure enclosed under v-t graph. Distance covered in 15s, s=ut=20×15=300m