6.
There is a current of 0.21 A in a copper wire
whose area of cross-section is 10-6m2. If the
number of free electrons per mº is 8.4x 1028,
then find the drift velocity
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Answered by
1
Answer:
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Answered by
1
Answer:
Number of free electrons n=8.4×10
22
×10
6
per m
3
=8.4×10
28
per m
3
Current in the wire I=0.21 A
Cross-section of the wire A=1mm
2
=10
−6
m
2
Thus drift velocity of electrons v=
neA
I
=
(8.4×10
28
)×(1.6×10
−19
)×(10
−6
)
0.21
=1.56×10
−5
m/s
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