Physics, asked by Zaid06, 2 months ago

6.
There is a current of 0.21 A in a copper wire
whose area of cross-section is 10-6m2. If the
number of free electrons per mº is 8.4x 1028,
then find the drift velocity

Answers

Answered by rohitsingh14072009
1

Answer:

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Answered by nihasrajgone2005
1

Answer:

Number of free electrons n=8.4×10

22

×10

6

per m

3

=8.4×10

28

per m

3

Current in the wire I=0.21 A

Cross-section of the wire A=1mm

2

=10

−6

m

2

Thus drift velocity of electrons v=

neA

I

=

(8.4×10

28

)×(1.6×10

−19

)×(10

−6

)

0.21

=1.56×10

−5

m/s

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