Question

6. Three consecutive numbers are such that the sum of the squares of the first two numbers is greater than the square of the third by 65. Find the numbers.* I want quality answer from regular users of brainly ; full support, thanks will be given and correct answer will be marked as brainliest...​

Answer 1

Answer:

I don't know your question please mark as brainy

Answer 2

Step-by-step explanation:

(x+4)^2 + 65 = x^2 + (x+2)^2

x^2 + 8x + 81 = 2x^2 + 4x + 4

0 = x^2 - 4x - 77

0 = (x-11)(x+7)

x = -7 (the given solution)

x = 11