Question

6. Twice a number added to half of itself equals 20. Find the number.​

Answer 1

Answer:

2x + x/2=20

(4x+x)/2=20

5x=40

x=8

Answer 2

Given:

• Twice a number added to half of itself equals 20

To Find:

• The number which satisfies the following statement mentioned above in the question

Solution:

Understanding the question:

Now, we have given that 2 of a number ( multipled by 2 of itself) added to half of itself ( multiplied by ½ of itself) gives the result as 20 finally and that we have to find the number

Assuming the number as ${\pink{\boxed{\sf{ x}}}}$ let's frame up an equation accordingly and start solving it to find the number required here

Let's frame an equation:

$\longrightarrow \tt \: 2x + \frac{1}{2} \times x = 20 \\ \\ \\ \longrightarrow \tt2x + \frac{x}{2} = 20 \: \: \: \: \: \: \: \: \: \\ \\ \\ \longrightarrow \tt \frac{2x \times 2}{1 \times 2} + \frac{x}{2} = 20 \\ \\ \\ \longrightarrow \tt \frac{4x + x}{2} = 20 \: \: \: \: \: \: \: \: \\ \\ \\ \longrightarrow \tt \: \frac{5x}{2} = 20 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \longrightarrow \tt \: 5x = 20 \times 2 \: \: \: \: \: \: \: \: \: \\ \\ \\ \longrightarrow \tt \: 5x = 40 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \longrightarrow \tt \: x = \cancel \frac{40}{5} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \longrightarrow \tt \: { \boxed{ \tt{x = 8}}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Hence:

• The Required Number is 8

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