Question

6. Two charges +5 uC and +10 uC are placed 20 cm apart
The net electric field at the mid-point between the two
charges is
(a) 4.5 x 10 NC directed towards +5uC
(b) 45x106 NC -' directed towards +10 LC
(c) 135 x 106 NC-1 directed towards +5 u
(d) 13.5 x 10 NC-' directed towards +10 uc
​

Answer 1

Answer:

B

Explanation:

As two charges as placed 20 cm = 0.2m

electric field due to first charge = 5*10^-6 *9*10^9 / 1*10^-2

45*10^5

electric field due to second charge = 90*10^5

net answer b