Question

6.
Two components in the ratio of x: y form an azeotropic mixture. They are mixed in the ratio
of x: 2y, how many moles one of the pure component y will be evaporated before getting
azeotropic solution?​

Answer 1

Answer ⇒ ny moles of second component will be evaporated, where n is the constant term...

Explanation ⇒ Azeotropic mixture is that in which the proportion of each component becomes same.

When the molar concentration is same then only they form azeotropes.

Thus, Azeotropes is formed for x/y or x : y.

When the concentration is in ratio x/2y then extra moles of second component = 2ny - ny = ny will get evaporated before the azeotropes of this mixture is formed.

[ n is the constant, since constant always comes when ratio is separated.]

This means, either we mix any concentration of two solutions, they may form azeotropes or constant boiling mixture after there molar concentration becomes same, i.e. there ratio becomes x : y.

Hope it helps.