Question

6. Two cross roads, each of width 10 m, cut at right angles through the centre of a
rectangular park of length 700 m and breadth 300 m and parallel to its sides. Find the
area of the roads. Also find the area of the park excluding cross roads. Give the
answer in hectares​

Answer 1

Answer:

20•01

Step-by-step explanation:

length length of rectangular roads =700m

breadth of rectagular road =300m

Area=l×b

=700×300

=210000

in rectangle EFGH=

l=700m

b=10m

Area=700×10

=7000mm

in rectangle PQRS

l=300m

=b=10m

area=l×b

300×10=

3000m

Now in square KLMN

side=10

10×10

=100m

In area of roads=210000(7000+3000-100)

210000-9900

201000

1m=10000 hectra

201000\10000

=20•01 hectra

Answer 2

$\huge{Solution}$

From the question it is given that,

Length of the park (L) = 700 m

Breadth of the park (B) = 300 m

Then,

Area of the park = length × breadth

= 700 × 300

= 210000 m^2

Let us assume that ABCD is the one cross road and EFGH is another cross road in the park.

• The length of ABCD cross road = 700 m
• The length of EFGH cross road = 300 m

Both cross road have the same width = 10 m

Then,

Area of the ABCD cross road = length × breadth

= 700 × 10

= 7000 m^2

Area of the EFGH cross road = length × breadth

= 300 × 10

= 3000 m^2

Area of the IJKL at center = length × breadth

= 10 × 10

= 100 m^2

Area of the roads = Area of ABCD + Area of EFGH – Area of IJKL

= 7000 + 3000 – 100

= 10000 – 100

= 9900 m^2

We know that, for 1 hectare = 10000 m^2

Hence, area of roads in hectare = 9900/10000

= 0.99 hectare

Finally, Area of the park excluding roads = Area of park – Area of the roads

= 210000 – 9900

= 200100 m^2

= 200100/10000

= 20.01 hectare