Question

6. Two dice are rolled, find the probability that the sum is
i) equal to 1
ii) equal to 4
iii) less than 13​

Answer 1

Answer:

1).....0

2)....4

3).....1

Answer 2

Since there are two dice and have 6 sides so,

Total combinations = 6 × 6 = 36

i) The minimum no. on dice is one and if we add both minimum no. of both dices, then it will be 2. so possible combination = 0

then,

P(getting sum 1) = 0 ÷ 36 = 0

ii) The combination in which the sum is equal to 4 are : (1,3), (3,1), (2,2)

so possible combination = 3

then,

P(getting sum 4) = 4 ÷ 36 ÷ 1 / 9

iii) The maximum no. on a dice is 6 and if both dice gets 6 then the total sum is 12, so every combination is less than 13

so possible combination = 36

then

P(getting sum less than 13) = 36 ÷ 36 = 1