Question

6. Two dice are thrown simultaneously. Find the probability of getting
a. Asum less than 6
b. A prime number as a sum
c. Amultiple of 3 as a sum​

Answer 1

Step-by-step explanation:

Total={(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)

(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)

(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)

(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)

(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)

(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)}

=36

a)Total={(1,1)(1,2)(1,3)(1,4)(2,1)(2,2)(2,3)(3,1)(3,2)(1,3)(4,1)}

=11

P=11/36

b)Total={(1,1)(1,2)(1,4)(1,6)(2,1)(2,3)(2,5)(3,2)(3,4)(4,1). (4,3)(5,2)(5,4)(5,6)(6,1)(6,5)}

=16

P=16/36=4/9

c)Total={(1,2)(1,5)(2,1)(2,4)(3,3)(3,6)(4,2)(4,5)(5,1)(5,4)(6,3)(6,6)}

=12

P=12/36=1/3