6) Two numbers are in the ratio of 7:5. If they differ by 16. What are the numbers?
Answers
Answered by
0
Answer:
Numbers are 56 and 40
Step-by-step explanation:
ATQ -
7x - 5x = 16
x = 8
Thus 7x = 56, 5x = 40
Answered by
0
Answer:
56, 40
Step-by-step explanation:
Let the mean ratio be x.
Therefore, 7x-5x= 16
=> 2x= 16
=> X= 8
Therefore, 7x= 7×8= 56
5x =5×8= 40
Please mark my answer as the brainliest
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