Question

6)
Two tuning forks with natural frequency of 440
Hz move relative to a stationary observer. One
tuning fork moves away from the observer and
the other moves towards the observer with the
same speed. If the observer hears beats of
frequency 4 Hz and assuming that the velocity of
the tuning forks is much smaller than the velocity
of sound, the speed (in m/s) of the tuning forks is
(Take velocity of sound in air is 340 m/s)
19
11
15
11
17
11
13​

Answer 1

Answer:

sorry can't help but think about it

Answer 2

Answer:

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