Question

6) Two years ago, father's age was four
times then age of the son. Three years
hence, the age of father will become
three times the age of son. What is the
sum of their present ages?​

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

let the father's age be 4x and son's age be x

after 10years

4x + 10 = 3 *(x+ 10)

4x+10= 3x +30

4x -3x = 30-10

x= 20

therefore father's present age = 4x

=4 * 20 = 80

son's present age = x=20