Question

6 under root 3 X square + 7 X equal to under root 3

Answer 1

Hi...☺️

Here is your answer...✌️

$6\sqrt{3} \: {x}^{2} + 7x = \sqrt{3} \\ \\ 6 \sqrt{3} \: {x}^{2} + 7x - \sqrt{3} = 0 \\ \\ 6 \sqrt{3} \: {x}^{2} + 9x - 2x - \sqrt{3} = 0 \\ \\ 3 \sqrt{3} \: x (2x + \sqrt{3} ) - 1(2x + \sqrt{3} ) = 0 \\ \\ ( 3 \sqrt{3} \: x - 1)(2x + \sqrt{3} ) = 0 \\ \\ = > 3 \sqrt{3} \: x - 1 = 0 \: \: or \: \: 2x + \sqrt{3} = 0 \\ \\ = > x = \frac{1}{3 \sqrt{3} } \: \: or \: \: x= \frac{ - \sqrt{3} }{2}$

Answer 2

x = 1/3√3 or -3/√2....