Question

6 upon 3 route 2 -2 route 3 = b route 2 -a route 3 . find A and B

Answer 1

Answer:

b=1 , a =2

Step-by-step explanation:

6/3√2 - 2√3 = b√2 - a√3

= 2/√2 - 2√3 = b √2 - a√3

= √2 - 2√3 = b√2 -a √3

From this

a is coefficient of √3

b is coefficient of √2

b=1

a=2

Answer 2

A = -2

B = 3

Step-by-step explanation:

We are given the following in the question:

$\dfrac{6}{3\sqrt{2}-2\sqrt{3}} = B\sqrt{2}-A \sqrt{3}$

We have to find the value of A and B.

Rationalizing the given fraction:

$\dfrac{6}{3\sqrt{2}-2\sqrt{3}}\times \dfrac{3\sqrt{2}+2\sqrt{3}}{3\sqrt{2}+2\sqrt{3}}\\\\= \dfrac{18\sqrt{2}+12\sqrt{3}}{18-12}\\\\= \dfrac{18\sqrt{2}+12\sqrt{3}}{6}\\\\=3\sqrt{2}+ 2\sqrt{3}$

Comparing, we get,

A = -2

B = 3

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