Question

6 upon 9√3 rationalize the denominator

Answer 1

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$= \frac{6}{9 \sqrt{3} } \\ = \frac{2}{3 \sqrt{3} } \\ = \frac{2 \sqrt{3} }{3 \sqrt{3} \times \sqrt{3} } \\ = \frac{2 \sqrt{3} }{9}$

$\large\mathcal\red{hope\: this \: helps \:you......}$

Answer 2

Answer:

hope this answer of mine helps you