Question

6.
Use factor theorem to factorise x² - 4x-5.​

Answer 1

Step-by-step explanation:

$x {}^{2} - 4x - 5 \\ x {}^{2} - 5x + 1x - 5 \\ x(x - 5) + 1(x - 5) \\ (x - 5) \: and \: (x + 1) \\ x = 5 \: and \: x = - 1$

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Answer 2

$\large{\underline{\boxed{\tt Answer}}}$

$(x-1) (x+5)$

Step-by-step explanation:

Given Problem:

Use factor theorem to factorise x² - 4x-5

Solution:

To Factorise:

Use factor theorem to factorise x² - 4x-5

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⇒According to your question,

We Have to use Factor theorem:

Method:

⇒ $x^2-4x-5$

⇒ $=x^2+5-x-5$

⇒ $=x(x+5)-1(x+5)$

⇒ $=(x-1) (x+5)$

Answer.

$(x-1) (x+5)$