6. Using the v-t graph, one can conclude v (m/s) 15 10 5 4 0 2 6 8 i (s) A: Displacement in (0-4) seconds is equal to the displacement in (4 - 6) seconds. B: Acceleration is 2.5 msain OA and zero in - AB. C: Acceleration is negative in time ( 6-8) seconds. (a) Only A is correct (b) Only B is correct (c) Only C is correct (d) All the three are correct.
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(1) OA represents uniform acceleration since the slope of OA in the velocity-time graph is having a uniform positive slope. AB represents the uniform velocity of 20ms−1. Since the slope of AB is zero. hence, acceleration is zero.
(2) After 10 s, the velocity is 20ms−1 up to 30 s and after 30 s, the velocity is uniformly restarted to zero after 40 s.
(3) Retardation is uniform and it is equal to the slope of BC, i.e.
Slope of BC =DCBD=40−3020=2ms−2
And acceleration =−2ms−2
(4) Distance covered by the body between the 10th and 30th second
=20×20=400metres
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