Question

6. Volume of 1 equivalent of Oz(g) at STP is​

Answer 1

Answer: It should be 5.6 L.

Explanation: Equivalent weight = Molecular weight ÷ total valency of molecule

Here , Eq. Weight = 32÷4 = 8 gm.

Now, volume of 32 gm of oxygen at STP Is 22.4l

So, volume of 8 gm of oxygen = 5.6 litres.