6. Volume of 1 equivalent of Oz(g) at STP is
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Answer: It should be 5.6 L.
Explanation: Equivalent weight = Molecular weight ÷ total valency of molecule
Here , Eq. Weight = 32÷4 = 8 gm.
Now, volume of 32 gm of oxygen at STP Is 22.4l
So, volume of 8 gm of oxygen = 5.6 litres.
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