Question

6.What are the final values stored in variables x and y below?

double a=-6.35;

double b=14.74;

double x= Math.abs(Math.ceil(a));

double y=Math.rint(Math.max(a,b));
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please show work ​

Answer 1

Answer:

x = Maths.abs(-7.0)

= 7.0

y = Math.rint(14.75)

= 14.0

I think so....

Answer 2

Required Answer:-

Question:

• Find the output of the following.

Output:

x = 6.0

y = 15.0

Explanation:

Given snippet,

double a = -6.35;

double b = 14.74;

double x = Math.abs(Math.ceil(a));

double y = Math.rint(Math.max(a,b));

Here,

➡ Math.ceil(a) = Math.ceil(-6.35) = -6.0

Therefore,

➡ Math.abs(-6.0) = 6.0 — (i)

• Math.ceil():- This function returns the higher integer for the given argument.
• As we know that, -6.0 > -6.35 (6.0 is on the right side of -6.35 in number line), so higher integer for this argument is -6.0
• So, Math.ceil(-6.35) returns -6.0

• Math.abs():- This function finds the absolute value of the number. Absolute value means the magnitude of number without it's sign.
• For example, Math.abs(-6) = 6, Math.abs(0) = 0, Math.abs(2) = 2.

★ So, the value of x is 6.0

Now,

➡ Math.max(a, b) = Math.max(-6.35, 14.74) = 14.74

Therefore,

Math.rint(14.74) = 15.0 — (ii)

• Note that Math.max(x, y) finds the highest value among two numbers.
• Here, 14.74 > -6.35. Therefore, Math.max() returned 14.74.

• Math.rint():- This function returns the nearest integer for the argument.
• For positive numbers, if the fractional part is between 0.0 and 0.5, then it returns the integer part for the number or else, it returns the next higher integer.
• For negative numbers, if the fractional part is between 0.0 and 0.5, then the function returns the integer part or else, it returns the lower integer.

• Here, fractional part of 14.74 is 0.74. It is not between 0.0 and 0.5, So the next number is returned i.e., 15.0. So, the output is 15.0

★ So, the value of y is 15.0.